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Puzzle Paradise

Group 2 "Bishop in a Hurry"

P2.1.1 P2.1.2 P2.2.1 P2.3.1 P2.5.1.1 P2.9.1 P2.12.1 P2.13.1

Reader's Challenge P2.1.1

M.Adams-P.Motwani, London 1989.

The idea of ...Na5 has been mentioned, but would it have been OK for Black to play it even earlier, at move three?










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Reader's Challenge P2.1.2

M.Adams-P.Motwani, London 1989.

If 35 Nf1










then how should Black continue?

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Reader's Challenge P2.2.1

G.Kamsky-A.Yusupov, Tilburg 1993

Another line is 27 Rd1 Rh8 28 Nf1,










and you are invited to now find a quick forced win for Black.

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Reader's Challenge P2.3.1










Philidor rejected 45...e3, but why?
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Reader's Challenge P2.5.1.1










Should Black now capture on e4 with his d-pawn?
Click here for the Solution

Reader's Challenge P2.9.1










Just imagine that right now Black could have an extra knight somewhere on the g-file. How many solutions can you find so that Black (to move) can force mate in two moves?

Answers appear at the end of the game G2.9.

Reader's Challenge P2.12.1










Can you now find a quick win for White? Look out...it's about to happen in the actual game G2.12!

Or Click here for the Solution

Reader's Challenge P2.13.1










Can you now find a quick win for White? Look out...it's about to happen in the actual game G2.13!

Or Click here for the Solution


Solutions

Solution to P2.1.1

M.Adams-P.Motwani, London 1989










3...Na5? loses to 4 Bxf7+! Kxf7 5 Qh5+, intending 5...g6 6 Qxe5+ (forking the loose black pieces on a5 and h8) or 5...Ke6 6 Qf5+ Kd6 7 d4 and then, for example, 7...Qf6 8 dxe5+ Qxe5 9 Bf4 or 7...Qe8 8 dxe5+ Kc6 9 e6 b6 10 Qd5# or 7...Nc6 8 dxe5+ Nxe5 9 Bf4 Qf6 10 Bxe5+ Qxe5 11 0-0-0+, costing Black his queen.

P2.1.1 P2.1.2 P2.2.1 P2.3.1 P2.5.1.1 P2.9.1 P2.12.1 P2.13.1

Solution to P2.1.2

M.Adams-P.Motwani, London 1989










Black neatly forces checkmate with 35...Rd2+! 36 Nxd2 (36 Kf3 Qf2#) 36...Qe3+ 37 Kd1 Qxd2# or 37 Kf1 Nxd2#.

P2.1.1 P2.1.2 P2.2.1 P2.3.1 P2.5.1.1 P2.9.1 P2.12.1 P2.13.1

Solution to P2.2.1

G.Kamsky-A.Yusupov, Tilburg 1993.










Black wins very quickly with 28...Nf3+ 29 gxf3 (29 Kh1 Qxh2+ 30 Nxh2 Rxh2#) 29...gxf3 30 Qd2 Qg4+ 31 Ng3 Rxh2! (this is clearer for Black than 31...Qh3 32 Nf5+) 32 Kxh2 Qh4+ 33 Kg1 Qxg3+ 34 Kf1 Qg2+ 35 Ke1 Qg1#.

P2.1.1 P2.1.2 P2.2.1 P2.3.1 P2.5.1.1 P2.9.1 P2.12.1 P2.13.1

Solution to P2.3.1










45...e3? would let White escape with a draw by playing 46 Rf8!.
P2.1.1 P2.1.2 P2.2.1 P2.3.1 P2.5.1.1 P2.9.1 P2.12.1 P2.13.1

Solution to P2.5.1.1










Black should not have played 5...dxe4?, as he soon discovered when Tibor Tolnai's reply 6 Ng5! quickly landed on the board!

Solution to P2.12.1










12 Qd7! f6 13 Nxf6 Flashier than 13 Nxc7. Black resigned, on account of 13...Nxf6 14 Rxf6+! gxf6 15 Bh6+ Kg8 16 Qe6#.

P2.1.1 P2.1.2 P2.2.1 P2.3.1 P2.5.1.1 P2.9.1 P2.12.1 P2.13.1

Solution to P2.13.1










8 Be6! Qe7 9 Nd5 wins quickly.

P2.1.1 P2.1.2 P2.2.1 P2.3.1 P2.5.1.1 P2.9.1 P2.12.1 P2.13.1